document.write( "Question 970669: How do you solve:
\n" ); document.write( "log2(3x+2)-log2(x)/log2(4)=3
\n" ); document.write( "3log2(x-1)+log2(4)=5
\n" ); document.write( "Logx(1/27)=3
\n" ); document.write( "5^(1-2x)=1/5 \n" ); document.write( "

Algebra.Com's Answer #593327 by stanbon(75887) $\"\"$ $\"About$

You can put this solution on YOUR website!
solve:
\n" ); document.write( "log2(3x+2)-log2(x)/log2(4) = 3
\n" ); document.write( "log2[(3x+2)/x] = log2(64)
\n" ); document.write( "-----
\n" ); document.write( "(3x+2)/x = 64
\n" ); document.write( "61x = 2
\n" ); document.write( "x = 2/61
\n" ); document.write( "-----------------
\n" ); document.write( "3log2(x-1)+log2(4) = 5
\n" ); document.write( "log2[(x-1)^3*4] = 5
\n" ); document.write( "------
\n" ); document.write( "4(x-1)^3 = 2^5
\n" ); document.write( "(x-1)^3 = 2^3
\n" ); document.write( "x-1 = 2
\n" ); document.write( "x = 3
\n" ); document.write( "----------------
\n" ); document.write( "Logx(1/27) = 3
\n" ); document.write( "x^3 = 1/27
\n" ); document.write( "x = 1/3
\n" ); document.write( "-------------------
\n" ); document.write( "5^(1-2x) = 1/5
\n" ); document.write( "5^(1-2x) = 5^-1
\n" ); document.write( "1-2x = -1
\n" ); document.write( "2x = 2
\n" ); document.write( "x = 1
\n" ); document.write( "-----------------
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( "----------------- \n" ); document.write( "

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