document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=970652>Question 970652</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve this equation on the interval 0 &#952; < 2&#960;. If there is no solution, enter NONE.<BR>\n" );
document.write( "cos(2&#952;) = cos &#952; \r<BR>\n" );
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document.write( " (smallest value)- ______________<BR>\n" );
document.write( "                 - ______________<BR>\n" );
document.write( " (largest value) - ______________ </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #593325 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=593325\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> cos 2x=2 cos^2x-1\r<BR>\n" );
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document.write( "2cos^2 x-1-cos x=0\r<BR>\n" );
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document.write( "2 cos^2 x- cos x -1=0  Factor.\r<BR>\n" );
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document.write( "(2cos x +1) (cos x-1)=0\r<BR>\n" );
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document.write( "cos x=1   cos x=(-1/2)\r<BR>\n" );
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document.write( "cos x=1 at 0 degrees   Cos 0 deg=cos 2*0 degrees\r<BR>\n" );
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document.write( "cos x=(-1/2) at pi/3 or 120 degrees.\r<BR>\n" );
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document.write( "cos x= (-1/2) at 2pi/3 or 240 degrees.\r<BR>\n" );
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document.write( "smallest value is 0<BR>\n" );
document.write( "largest value is 2 pi/3 </SPAN>\n" );
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