document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=970701>Question 970701</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If the surface area of a shere is increased by 44%,find the percentage increase in its diameter. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #593319 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=593319\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Area = 4 pi *r^2<BR>\n" );
document.write( "1.44 area=4 pi *R^2<BR>\n" );
document.write( "Ratio of second to first<BR>\n" );
document.write( "1.44= (R/r)^2, where R is the new radius.\r<BR>\n" );
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document.write( "1.44 r^2+ R^2\r<BR>\n" );
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document.write( "Take the square root of both sides\r<BR>\n" );
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document.write( "1.2 r=R<BR>\n" );
document.write( "Diameter=2r=2.4, but it is still a 20% increase, since radius and diameter are linearly related.\r<BR>\n" );
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document.write( "Percentage of increase of diameter is 20%\r<BR>\n" );
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