document.write( "Question 970647:
\n" ); document.write( "Travis made a business trip of 198 miles. He averaged 52 mph for the first part of the trip and 60 mph for the second part. If the trip took 3.5 hours , how long did he travel at each rate?
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Algebra.Com's Answer #593297 by checkley77(12844)\"\" \"About 
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D=RT
\n" ); document.write( "198=(52X)+(60*(3.5-X))
\n" ); document.write( "198=52X+210-60X
\n" ); document.write( "210-198=60X-52X
\n" ); document.write( "12=8X
\n" ); document.write( "X=12/8
\n" ); document.write( "X=1.5 HOURS F0R THE 52 MPH TRIP.
\n" ); document.write( "3.5-1.5=2 HOURS FOR THE 60 MPH TRIP.
\n" ); document.write( "PROOF:
\n" ); document.write( "198=52*1.5+60*2
\n" ); document.write( "198=78+120
\n" ); document.write( "198=198
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