document.write( "Question 970647:
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document.write( "Travis made a business trip of 198 miles. He averaged 52 mph for the first part of the trip and 60 mph for the second part. If the trip took 3.5 hours , how long did he travel at each rate? \n" );
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Algebra.Com's Answer #593297 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! D=RT \n" ); document.write( "198=(52X)+(60*(3.5-X)) \n" ); document.write( "198=52X+210-60X \n" ); document.write( "210-198=60X-52X \n" ); document.write( "12=8X \n" ); document.write( "X=12/8 \n" ); document.write( "X=1.5 HOURS F0R THE 52 MPH TRIP. \n" ); document.write( "3.5-1.5=2 HOURS FOR THE 60 MPH TRIP. \n" ); document.write( "PROOF: \n" ); document.write( "198=52*1.5+60*2 \n" ); document.write( "198=78+120 \n" ); document.write( "198=198 \n" ); document.write( " |