document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=970692>Question 970692</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do you find the Vertex, focus, directric of the parabola and sketch its graph for the below equation?<BR>\n" );
document.write( "y=2x^2\r<BR>\n" );
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document.write( "Vertex: ______<BR>\n" );
document.write( "Focus: _____<BR>\n" );
document.write( "Directrix _______<BR>\n" );
document.write( "Axis of Symmetry: Vertical or Horizontal\r<BR>\n" );
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document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #593286 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=593286\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  How do you find the Vertex, focus, directrix of the parabola? Sketch its graph for the below equation?<BR>\n" );
document.write( "y=2x^2 <BR>\n" );
document.write( "Vertex: ______<BR>\n" );
document.write( "vertex occurs where x = -b/(2a) = -0/4 = 0<BR>\n" );
document.write( "then f(0) = 0<BR>\n" );
document.write( "So the vertex is (0,0)<BR>\n" );
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document.write( "Focus: _____<BR>\n" );
document.write( "Write the equation is vertex form::<BR>\n" );
document.write( "(x-0)^2 = (1/2)(y-0)<BR>\n" );
document.write( "Then 4p = 1/2, so p  = 1/8<BR>\n" );
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document.write( "Focus is at (0,0+p) = (0,1/8)<BR>\n" );
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document.write( "Directrix _______<BR>\n" );
document.write( "Directrix is y = 0-p = -1/8<BR>\n" );
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document.write( "Axis of Symmetry: Vertical or Horizontal<BR>\n" );
document.write( "The vertical axis of symmetry is x = 0<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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