document.write( "Question 970668: Solve the following polynomial equation. show your work.
\n" ); document.write( "x^3+x^2+2x-4=0 \n" ); document.write( "

Algebra.Com's Answer #593277 by Boreal(15235) $\"\"$ $\"About$

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The possible factors are +/- 1 +/-2 and +/-4\r
\n" ); document.write( "\n" ); document.write( "Let's try (x-1)\r
\n" ); document.write( "\n" ); document.write( "1 ;; 1 ;; 1 ;2 ;;-4
\n" ); document.write( "============1 ==2 ;=4 \r
\n" ); document.write( "\n" ); document.write( "====== 1===2==4==0\r
\n" ); document.write( "\n" ); document.write( "(x-1) (x^2+2x+4)=0\r
\n" ); document.write( "\n" ); document.write( "One root is 1; the second does not factor (4ac is larger than b^2=see below)\r
\n" ); document.write( "\n" ); document.write( "The quadratic formula for the other 2
\n" ); document.write( "=[-2 +/- sqrt (4-16)]/2 ;; sqrt (-12)=sqrt (3)* sqrt (-4)= 2i (sqrt (3)\r
\n" ); document.write( "\n" ); document.write( "-1 +/- i* sqrt (3)\r
\n" ); document.write( "\n" ); document.write( " $\"graph+%28300%2C300%2C-10%2C10%2C-10%2C10%2Cx%5E3%2Bx%5E2%2B2x-4%29\"$ \r
\n" ); document.write( "\n" ); document.write( "See a graph of a cubic equation with a root at x=1 and the y-intercept at (0.-4) consistent with the equation \n" ); document.write( "

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