document.write( "Question 970639: solve the equation.
\n" ); document.write( "log 1/5(x^2+x)- log 1/5(x^2-x)=-1 \n" ); document.write( "

Algebra.Com's Answer #593243 by khai(18) $\"\"$ $\"About$

You can put this solution on YOUR website!
first of all, is that a natural log (base 10) ? the way you write makes me confuse... if yes,
\n" ); document.write( "log (1/5) [(x^2+x)-(x^2-x)] = -1
\n" ); document.write( "log (1/5) [x^4-x^2] = -1
\n" ); document.write( "10^(-1) = (1/5)( x^4-x^2)
\n" ); document.write( "1/10 = (1/5) (x^4-x^2)
\n" ); document.write( "1/2 = (x^4-x^2)
\n" ); document.write( "x = -1.169 (2 multiplicity)
\n" ); document.write( "x = 1.169 (2 multiplicity)\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "

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