document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=970614>Question 970614</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A cone has a diameter of 16 in. and a slant height of 17 in.\r<BR>\n" );
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document.write( "What is the approximate volume of the cone?  Use 3.14 to approximate the value of straight pi. Round your answer to the nearest tenth, if necessary. (Hint: V equals 1 third straight pi r squared h )<BR>\n" );
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document.write( "  A. <BR>\n" );
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document.write( "1004.8 in3<BR>\n" );
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document.write( "  B. <BR>\n" );
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document.write( "1138.8 in3<BR>\n" );
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document.write( "  C. <BR>\n" );
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document.write( "1259.3 in3<BR>\n" );
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document.write( "4019.2 in3<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #593213 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=593213\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <BR>\n" );
document.write( " A cone has a diameter of 16 in. and a slant height of 17 in. \r<BR>\n" );
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document.write( " What is the approximate volume of the cone?<BR>\n" );
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document.write( "Find the height.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=h+=+sqrt%2817%5E2+-+8%5E2%29 ALIGN=MIDDLE  ALT=\"h+=+sqrt%2817%5E2+-+8%5E2%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=Vol+=+pi%2Ar%5E2%2Ah%2F3 ALIGN=MIDDLE  ALT=\"Vol+=+pi%2Ar%5E2%2Ah%2F3\"   DISABLED_style= \"max-width:90%; height:auto;\" > </SPAN>\n" );
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