document.write( "Question 970535: Solve the system { 2x-3y=5
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Algebra.Com's Answer #593165 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!
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Solved by pluggable solver: Solving a System of Linear Equations by Elimination/Addition

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\n" ); document.write( " Lets start with the given system of linear equations
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\n" ); document.write( " \"2%2Ax-3%2Ay=5\"
\n" ); document.write( " \"4%2Ax%2B5%2Ay=6\"
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\n" ); document.write( " In order to solve for one variable, we must eliminate the other variable. So if we wanted to solve for y, we would have to eliminate x (or vice versa).
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\n" ); document.write( " So lets eliminate x. In order to do that, we need to have both x coefficients that are equal but have opposite signs (for instance 2 and -2 are equal but have opposite signs). This way they will add to zero.
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\n" ); document.write( " So to make the x coefficients equal but opposite, we need to multiply both x coefficients by some number to get them to an equal number. So if we wanted to get 2 and 4 to some equal number, we could try to get them to the LCM.
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\n" ); document.write( " Since the LCM of 2 and 4 is 4, we need to multiply both sides of the top equation by 2 and multiply both sides of the bottom equation by -1 like this:
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\n" ); document.write( " \"2%2A%282%2Ax-3%2Ay%29=%285%29%2A2\" Multiply the top equation (both sides) by 2
\n" ); document.write( " \"-1%2A%284%2Ax%2B5%2Ay%29=%286%29%2A-1\" Multiply the bottom equation (both sides) by -1
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\n" ); document.write( " So after multiplying we get this:
\n" ); document.write( " \"4%2Ax-6%2Ay=10\"
\n" ); document.write( " \"-4%2Ax-5%2Ay=-6\"
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\n" ); document.write( " Notice how 4 and -4 add to zero (ie \"4%2B-4=0\")
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\n" ); document.write( " Now add the equations together. In order to add 2 equations, group like terms and combine them
\n" ); document.write( " \"%284%2Ax-4%2Ax%29-6%2Ay-5%2Ay%29=10-6\"
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\n" ); document.write( " \"%284-4%29%2Ax-6-5%29y=10-6\"
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\n" ); document.write( " \"cross%284%2B-4%29%2Ax%2B%28-6-5%29%2Ay=10-6\" Notice the x coefficients add to zero and cancel out. This means we've eliminated x altogether.
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\n" ); document.write( " So after adding and canceling out the x terms we're left with:
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\n" ); document.write( " \"-11%2Ay=4\"
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\n" ); document.write( " \"y=4%2F-11\" Divide both sides by \"-11\" to solve for y
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\n" ); document.write( " \"y=-4%2F11\" Reduce
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\n" ); document.write( " Now plug this answer into the top equation \"2%2Ax-3%2Ay=5\" to solve for x
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\n" ); document.write( " \"2%2Ax-3%28-4%2F11%29=5\" Plug in \"y=-4%2F11\"
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\n" ); document.write( " \"2%2Ax%2B12%2F11=5\" Multiply
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\n" ); document.write( " \"2%2Ax%2B12%2F11=5\" Reduce
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\n" ); document.write( " \"2%2Ax=5-12%2F11\" Subtract \"12%2F11\" from both sides
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\n" ); document.write( " \"2%2Ax=55%2F11-12%2F11\" Make 5 into a fraction with a denominator of 11
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\n" ); document.write( " \"2%2Ax=43%2F11\" Combine the terms on the right side
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\n" ); document.write( " \"cross%28%281%2F2%29%282%29%29%2Ax=%2843%2F11%29%281%2F2%29\" Multiply both sides by \"1%2F2\". This will cancel out \"2\" on the left side.
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\n" ); document.write( " \"x=43%2F22\" Multiply the terms on the right side
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\n" ); document.write( " So our answer is
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\n" ); document.write( " \"x=43%2F22\", \"y=-4%2F11\"
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\n" ); document.write( " which also looks like
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\n" ); document.write( " (\"43%2F22\", \"-4%2F11\")
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\n" ); document.write( " Notice if we graph the equations (if you need help with graphing, check out this solver)
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\n" ); document.write( " \"2%2Ax-3%2Ay=5\"
\n" ); document.write( " \"4%2Ax%2B5%2Ay=6\"
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\n" ); document.write( " we get
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\n" ); document.write( " graph of \"2%2Ax-3%2Ay=5\" (red) \"4%2Ax%2B5%2Ay=6\" (green) (hint: you may have to solve for y to graph these) and the intersection of the lines (blue circle).
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\n" ); document.write( " and we can see that the two equations intersect at (\"43%2F22\",\"-4%2F11\"). This verifies our answer.
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