document.write( "Question 970527: The distance between the points (-1,5) and -3,-1) is:\r
\n" ); document.write( "\n" ); document.write( "Do you subtract the x and y to find this? Like -1--3 = 1
\n" ); document.write( "and 5--1-6 so would the answer be 1,6?\r
\n" ); document.write( "\n" ); document.write( "thank you
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Algebra.Com's Answer #593141 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
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Solved by pluggable solver: Distance Formula

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\n" ); document.write( " The first point is (x1,y1). The second point is (x2,y2)
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\n" ); document.write( " Since the first point is (-1, 5), we can say (x1, y1) = (-1, 5)
\n" ); document.write( " So \"x%5B1%5D+=+-1\", \"y%5B1%5D+=+5\"
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\n" ); document.write( " Since the second point is (-3, -1), we can also say (x2, y2) = (-3, -1)
\n" ); document.write( " So \"x%5B2%5D+=+-3\", \"y%5B2%5D+=+-1\"
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\n" ); document.write( " Put this all together to get: \"x%5B1%5D+=+-1\", \"y%5B1%5D+=+5\", \"x%5B2%5D+=+-3\", and \"y%5B2%5D+=+-1\"
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\n" ); document.write( " Now use the distance formula to find the distance between the two points (-1, 5) and (-3, -1)
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\n" ); document.write( " \"d+=+sqrt%28%28x%5B1%5D-x%5B2%5D%29%5E2+%2B+%28y%5B1%5D+-+y%5B2%5D%29%5E2%29\"
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\n" ); document.write( " \"d+=+sqrt%28%28-1+-+%28-3%29%29%5E2+%2B+%285+-+%28-1%29%29%5E2%29\" Plug in \"x%5B1%5D+=+-1\", \"y%5B1%5D+=+5\", \"x%5B2%5D+=+-3\", and \"y%5B2%5D+=+-1\"
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\n" ); document.write( " \"d+=+sqrt%28%28-1+%2B+3%29%5E2+%2B+%285+%2B+1%29%5E2%29\"
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\n" ); document.write( " \"d+=+sqrt%28%282%29%5E2+%2B+%286%29%5E2%29\"
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\n" ); document.write( " \"d+=+sqrt%284+%2B+36%29\"
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\n" ); document.write( " \"d+=+sqrt%2840%29\"
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\"d+=+sqrt%284%2A10%29\"


\"d+=+sqrt%284%29%2Asqrt%2810%29\"


\"d+=+2%2Asqrt%2810%29\"


\n" ); document.write( " \"d+=+6.32455532033676\"
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\n" ); document.write( " Answer:
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\n" ); document.write( " The distance between the two points (-1, 5) and (-3, -1) is exactly \"2%2Asqrt%2810%29\" units
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\n" ); document.write( " The approximate distance between the two points is about 6.32455532033676 units
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\n" ); document.write( " So again,
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\n" ); document.write( " Exact Distance: \"2%2Asqrt%2810%29\" units
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\n" ); document.write( " Approximate Distance: \"6.32455532033676\" units
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