document.write( "Question 970458: A cone has a diameter of 16 in. and a slant height of 17 in.\r
\n" ); document.write( "\n" ); document.write( " \r
\n" ); document.write( "\n" ); document.write( "What is the approximate volume of the cone? Use 3.14 to approximate the value of straight pi. Round your answer to the nearest tenth, if necessary. (Hint: V equals 1 third straight pi r squared h )
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " http://static.k12.com/calms_media/media/1579000_1579500/1579259/1/46806957cc283c004d05d6ee809afdbfc595c4d4/MS_IMC-150123-1306013.jpg
\n" ); document.write( " \r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( " \r
\n" ); document.write( "\n" ); document.write( " \r
\n" ); document.write( "\n" ); document.write( " A.
\n" ); document.write( "
\n" ); document.write( "1004.8 in3
\n" ); document.write( "
\n" ); document.write( " \r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( " \r
\n" ); document.write( "\n" ); document.write( " \r
\n" ); document.write( "\n" ); document.write( " B.
\n" ); document.write( "
\n" ); document.write( "1138.8 in3
\n" ); document.write( "
\n" ); document.write( " \r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( " \r
\n" ); document.write( "\n" ); document.write( " \r
\n" ); document.write( "\n" ); document.write( " C.
\n" ); document.write( "
\n" ); document.write( "1259.3 in3
\n" ); document.write( "
\n" ); document.write( " \r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( " \r
\n" ); document.write( "\n" ); document.write( " \r
\n" ); document.write( "\n" ); document.write( " D.
\n" ); document.write( "
\n" ); document.write( "4019.2 in3
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #593106 by josgarithmetic(39618)\"\" \"About 
You can put this solution on YOUR website!
Notice the triangle formed, AED is a right triangle. You can find h, the height using Pythagorean Theorem.
\n" ); document.write( "Triangle BED is congruent to triangle AED.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"h%5E2%2B%2816%2F2%29%5E2=17%5E2\"
\n" ); document.write( "\"h%5E2=17%5E2-8%5E2\"
\n" ); document.write( "\"h=sqrt%2817%5E2-64%29\"
\n" ); document.write( "\"h=sqrt%28225%29\"
\n" ); document.write( "\"h=15\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "volume of the cone is \"%281%2F3%29h%2Api%28r%5E2%29\"------excuse the rendering; pi is a factor, NOT an exponent;
\n" ); document.write( "volume is \"%281%2F3%29%2A15%2Api%2A%288%5E2%29\"
\n" ); document.write( "\"5%2Api%2A64\"
\n" ); document.write( "\"highlight%28320%2Api%29\".
\n" ); document.write( "
\n" );