document.write( "Question 970463: obtain the term involving x^3 in expansion of (2x-1/2)^7
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Algebra.Com's Answer #593095 by Boreal(15235) You can put this solution on YOUR website! binomial expansion\r \n" ); document.write( "\n" ); document.write( "1 \n" ); document.write( "1 2 1 \n" ); document.write( "1 3 3 1 \n" ); document.write( "1;; 4;; 6 ;; 4; 1 \n" ); document.write( "1; 5; 10;; 10 ;;5;; 1 \n" ); document.write( "1 ;;6;; 15;; 20;; 15;; 6 ;;1 \n" ); document.write( "1 ;;7 ;;21;; 35;; 35;; 21;; 7;; 1\r \n" ); document.write( "\n" ); document.write( "(2x) is the leading term \n" ); document.write( "The first term is (2x)^7 \n" ); document.write( "The second term is 7 (2x)^6 \n" ); document.write( "The x^3 term is the fifth number in the sequence \n" ); document.write( "it is 35 (2x)^3\r \n" ); document.write( "\n" ); document.write( "Remember that the 2 has to be cubed as well \n" ); document.write( "So the term involving x^3 is 280 x^3 \n" ); document.write( " |