document.write( "Question 970469: Find the surface area and volume of a sphere whose great circle has a circumference of 28 meters \n" ); document.write( "
Algebra.Com's Answer #593083 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! A=4 pi * r^2\r \n" ); document.write( "\n" ); document.write( "circumference=28 m \n" ); document.write( "C=2pi*r\r \n" ); document.write( "\n" ); document.write( "r=C/2pi \n" ); document.write( "r=28/2pi or 14/pi\r \n" ); document.write( "\n" ); document.write( "A= 4* pi * (14/pi)^2= 4*pi * (196/pi^2)= 784/pi, since there is one pi in the numerator and one in the denominator\r \n" ); document.write( "\n" ); document.write( "A=249.55 sq m.\r \n" ); document.write( "\n" ); document.write( "V=(4/3) pi r^3 \n" ); document.write( "=(4/3) pi* (14/pi)^3 \n" ); document.write( "numerator is 4*14^3*pi \n" ); document.write( "denominator is 3* pi^3\r \n" ); document.write( "\n" ); document.write( "=4*14^3/[3*pi^2]=10976/29.61\r \n" ); document.write( "\n" ); document.write( "=370.69 m^3\r \n" ); document.write( "\n" ); document.write( "The ratio of the area to the volume is 4*pi*r^2/(4/3)pi*r^3=3/r\r \n" ); document.write( "\n" ); document.write( "(3/r) =3/(14/pi) =3 *pi/14 or 67.3%\r \n" ); document.write( "\n" ); document.write( "Area to volume is 249.55/370.69 \n" ); document.write( "This is 67.3%. This doesn't prove the numbers are correct; it does show that the manipulation of each formula came up with the ratio is should. \n" ); document.write( " \n" ); document.write( " |