document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=970445>Question 970445</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a rectangle is 6 inches longer than it is wide the area of the reran gel is 112 square inches find the length and width of the rectangle<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #593081 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=593081\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> L*w=Area=112 in^2\r<BR>\n" );
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document.write( "w<BR>\n" );
document.write( "L=w +6\r<BR>\n" );
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document.write( "w(w+6)=112<BR>\n" );
document.write( "w^2+6w-112=0   This is distributing the w and subtracting 112 from both sides.  I now have a quadratic equation.\r<BR>\n" );
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document.write( "Factor it\r<BR>\n" );
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document.write( "4/23  no  8/14 yes\r<BR>\n" );
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document.write( "(w+14)(w-8)=0   ; This works if either w+14 or w-6=0\r<BR>\n" );
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document.write( "w=-14, w=8  ; only the second makes sense\r<BR>\n" );
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document.write( "length=8+6=14\r<BR>\n" );
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document.write( "14*8=112  (in*in=in^2).\r<BR>\n" );
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document.write( "The length is 14 and the width is 8<BR>\n" );
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