document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=970380>Question 970380</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the value of tan2x on the interval (pi/2,pi) given that sin=(1/2) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #593039 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=593039\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Find the value of tan2x on the interval (pi/2,pi) given that sin=(1/2)<BR>\n" );
document.write( "sinx=1/2 (Q2)<BR>\n" );
document.write( "cosx=-&#8730;3/2<BR>\n" );
document.write( "sin2x=2sinxcosx=2*1/2*-&#8730;3/2=-&#8730;3/2<BR>\n" );
document.write( "cos2x=cos^(x)-sin^2(x)=3/4-1/4=1/2<BR>\n" );
document.write( "tan2x=sin2x/cos2x=-&#8730;3 </SPAN>\n" );
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