document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=82211>Question 82211</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Evaluate the function without using a calculator.\r<BR>\n" );
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document.write( "Sin 300° </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #59300 by </B><A HREF=/tutors/aboutme.mpl?userid=kev82><B>kev82(151)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=kev82><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=59300\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Hi,<br />\r<BR>\n" );
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document.write( "There are 360 degrees in a circe, right? So going around a circle 300 degrees one way, is the same as going 60 degrees the other way. So sin(300)=sin(-60). Now you should know that sin(-x)=-sin(x). So we are down to sin(300)=-sin(60). You should also know that sin(60)=<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\sqrt{3}/2\"> so the answer is:<br />\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?sin(300)=-\frac{\sqrt{3}}{2}\"><br />\r<BR>\n" );
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document.write( "Hope that helps,<BR>\n" );
document.write( "Kev   </SPAN>\n" );
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