document.write( "Question 970351: Show that C(n,r)= C(n-1,r-1)+C(n-1,r)\r
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Algebra.Com's Answer #592999 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\"C%28n%2Cr%29+=+%28n%21%29%2F%28r%21%2A%28n-r%29%21%29\" by definition\r
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\n" ); document.write( "\n" ); document.write( "\"C%28n%2Cr%29+=+%28n%21%29%2F%28r%21%2A%28n-r%29%21%29\"\r
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\n" ); document.write( "\n" ); document.write( " Replace every 'n' with 'n-1'. Replace every 'r' with 'r-1'\r
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\n" ); document.write( "\n" ); document.write( "\"C%28n-1%2Cr-1%29+=+%28%28n-1%29%21%29%2F%28%28r-1%29%21%2A%28+n+-+1+-+r+%2B+1+%29%21%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"C%28n-1%2Cr-1%29+=+%28%28n-1%29%21%29%2F%28%28r-1%29%21%2A%28n+-+r%29%21%29\" I'm going to call this equation Q\r
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\n" ); document.write( "\n" ); document.write( "\"C%28n%2Cr%29+=+%28n%21%29%2F%28r%21%2A%28n-r%29%21%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"C%28n-1%2Cr%29+=+%28%28n-1%29%21%29%2F%28r%21%2A%28+n+-+1+-+r+%29%21%29\" Replace every 'n' with 'n-1'. I'm going to call this equation R\r
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\n" ); document.write( "\n" ); document.write( "we will use these ideas\r
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\n" ); document.write( "\n" ); document.write( "\"n%21+=+n%2A%28n-1%29%21\"\r
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\n" ); document.write( "\n" ); document.write( "\"r%21+=+r%2A%28r-1%29%21\"\r
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\n" ); document.write( "\n" ); document.write( "\"%28n-r%29%21+=+%28n-r%29%2A%28n+-+r-1%29%21\"\r
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\n" ); document.write( "\n" ); document.write( "to help us do the proof.\r
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\n" ); document.write( "\n" ); document.write( "Now onto the main proof. I'm only going to manipulate the right side of the equation to transform it into the left side.\r
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\n" ); document.write( "\n" ); document.write( "\"C%28n%2Cr%29+=+C%28n-1%2Cr-1%29%2BC%28n-1%2Cr%29\"\r
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\n" ); document.write( "\n" ); document.write( " Substitute equation Q and equation R (see above)\r
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\n" ); document.write( "\n" ); document.write( " Use the tricks shown above (eg: to write \"r%21\" as \"r%2A%28r-1%29%21\").\r
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\n" ); document.write( "\n" ); document.write( " I'm highlighting the common terms (shared between the fractions) in red\r
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\n" ); document.write( "\n" ); document.write( " Factor out the common terms\r
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\n" ); document.write( "\n" ); document.write( "\"C%28n%2Cr%29+=+%28+n%21+%29%2F%28+r%21+%2A+%28n-r%29%21+%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"C%28n%2Cr%29+=+C%28n%2Cr%29\" So the identity is confirmed.
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