document.write( "Question 970004: Two rectangles have the same width. The length of one is 1 foot longer than the width. The length of the other is 2 feet longer than the width. The larger rectangle has 5 more square feet than the smaller. What is the width of the rectangles?
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Algebra.Com's Answer #592978 by ankor@dixie-net.com(22740)\"\" \"About 
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Two rectangles have the same width.
\n" ); document.write( " The length of one is 1 foot longer than the width.
\n" ); document.write( " The length of the other is 2 feet longer than the width.
\n" ); document.write( " The larger rectangle has 5 more square feet than the smaller.
\n" ); document.write( " What is the width of the rectangles?
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\n" ); document.write( "Let x = the width of the 1st & 2nd rectangles
\n" ); document.write( "then
\n" ); document.write( "(x+1) = the length of the 1st rect
\n" ); document.write( "and
\n" ); document.write( "(x+2) = the length of the 2nd rect
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\n" ); document.write( "2nd area - 1st area = 5 sq/ft
\n" ); document.write( "x(x+2) - x(x+1) = 5
\n" ); document.write( "x^2 + 2x - x^2 - x = 5
\n" ); document.write( "combine like terms
\n" ); document.write( "x = 5 ft is the width of the rectangles
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\n" ); document.write( "See if that checks out, find the area of each rect
\n" ); document.write( "2nd rect: 7 * 5 = 35
\n" ); document.write( "1st rect: 6 * 5 = 30
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\n" ); document.write( "Area difference: 5 sq/ft
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