document.write( "Question 970320: Two planes leave an airport at the same time, one flying due west at 500 km/h and the other flying due southeast at 300 km/h. What is the distance between the planes two hours later. What do I do if there is no angle because I have to use trig. Please help. \n" ); document.write( "
Algebra.Com's Answer #592968 by Boreal(15235) You can put this solution on YOUR website! W+++Start \n" ); document.write( " ;;;;;;;;+ \n" ); document.write( " ;;;;;;;;;;;;;+SE\r \n" ); document.write( "\n" ); document.write( "The angle between SE and W is 135 degrees. SE is half way between E (90) and S (180)\r \n" ); document.write( "\n" ); document.write( "Two hours later, the plane flying west has gone 1000 km; the one SE 600 km. If they were in opposite directions, the distance would be 1600 km; the same direction and it would be 400 km, so the answer is between these values and closer to 1600 km by the picture above.\r \n" ); document.write( "\n" ); document.write( "The angle between them is 135 degrees\r \n" ); document.write( "\n" ); document.write( "The side you want is c. \n" ); document.write( "a=1000 \n" ); document.write( "b=600 \n" ); document.write( "the angle between is theta, and it is 135 degrees cos (135)=-(sqrt(2)/2))\r \n" ); document.write( "\n" ); document.write( "C^2=a^2 +b^2-2ab cos theta LAW OF COSINES\r \n" ); document.write( "\n" ); document.write( "c^2=1000000+360000+2(1000)(600)(.7071) ; .7071 is sqrt (2)/2. The last term is positive, because the cosine is negative, and there are two negatives. \n" ); document.write( "c^2=1360000+848520=2208520.\r \n" ); document.write( "\n" ); document.write( "c=1486.1 miles. \n" ); document.write( "This makes intuitive sense.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |