document.write( "Question 970293: Solve the equation for exact values: 2cos^2(x) - 2sin^2(x) + 2 = 0
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document.write( "Select one:
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document.write( "a. π
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document.write( "b. 0
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document.write( "c. π/2
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document.write( "d. 2π
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document.write( "
Algebra.Com's Answer #592951 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! 2cos^2(x) - 2sin^2(x) + 2 = 0 \n" ); document.write( "cos^2(x) - sin^2(x) + 1 = 0 \n" ); document.write( "--- \n" ); document.write( "cos^2 + sin^2 = 1 \n" ); document.write( "---- \n" ); document.write( "cos^2(x) - sin^2(x) + cos^2(x) + sin^2(x) = 0 \n" ); document.write( "2cos^2(x) = 0 \n" ); document.write( "cos(x) = 0 \n" ); document.write( "x = pi/2 ± n*pi, n = 0,1,2,3... \n" ); document.write( " |