document.write( "Question 970270: in a biathlon run over a 16 km (each way) course, the first half is the outgoing leg which is running and the returns section is covered by bicycle. Sam takes 1 hour 15 min. on the run leg. What speed must Sam cycle the returns leg to bring about a 50% improvement on his average speed for the entire race ? \n" ); document.write( "
Algebra.Com's Answer #592922 by ankor@dixie-net.com(22740)\"\" \"About 
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In a biathlon run over a 16 km (each way) course, the first half is the outgoing leg which is running and the returns section is covered by bicycle.
\n" ); document.write( " Sam takes 1 hour 15 min. on the run leg.
\n" ); document.write( " What speed must Sam cycle the returns leg to bring about a 50% improvement on his average speed for the entire race ?
\n" ); document.write( ":
\n" ); document.write( "Find the average speed on the run leg, 1 hr 15min = 1.25 hrs
\n" ); document.write( "16/1.25 = 12.8 km/hr
\n" ); document.write( "Find the 50% improvement in speed
\n" ); document.write( "1.5 * 12.8 = 19.2 km/hr
\n" ); document.write( ":
\n" ); document.write( "let s = speed required on the return trip to average 19.2 km/hr
\n" ); document.write( "Write a time equation; time = dist/speed
\n" ); document.write( ":
\n" ); document.write( "run time + bike time = total time
\n" ); document.write( "\"16%2F12.8\" + \"16%2Fs\" = \"32%2F19.2\"
\n" ); document.write( "Reduce fractions
\n" ); document.write( "\"5%2F4\" + \"16%2Fs\" = \"5%2F3\"
\n" ); document.write( "multiply by 12s, cancel the denominators and we have
\n" ); document.write( "3s(5) + 12(16) = 4s(5)
\n" ); document.write( "15s + 192 = 20s
\n" ); document.write( "192 = 20s - 15s
\n" ); document.write( "192 = 5s
\n" ); document.write( "s = 192/5
\n" ); document.write( "s = 38.4 km/hr, ride his bike on the return leg to average 19.2 km/hr\r
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