document.write( "Question 970250: Two sreetcars are 11 miles apart and traveling toward each other on parallel tracks. They meet in 12 minutes. Find the speed of each streetcar if one travels 15 miles per hour faster than the other. \n" ); document.write( "
Algebra.Com's Answer #592904 by josmiceli(19441)\"\" \"About 
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Think of this as one of the streetcars standing
\n" ); document.write( "still and the other moving at the sum of their speeds
\n" ); document.write( "Let \"+s+\" = the speed of the slower one
\n" ); document.write( "\"+s+%2B+15+\" = the speed of the faster one
\n" ); document.write( "-------------------------------------
\n" ); document.write( "Convert minutes to hrs:
\n" ); document.write( "\"+12%2F60+=+1%2F5+\" hrs
\n" ); document.write( "----------------------
\n" ); document.write( "\"+11+=+%28+s+%2B+s+%2B+15+%29%2A%28+1%2F5+%29+\"
\n" ); document.write( "\"+55+=+2s+%2B+15+\"
\n" ); document.write( "\"+2s+=+40+\"
\n" ); document.write( "\"+s+=+20+\"
\n" ); document.write( "and
\n" ); document.write( "\"+s+%2B+15+=+35+\"
\n" ); document.write( "--------------------
\n" ); document.write( "Their speeds are:
\n" ); document.write( "20 mi/hr and
\n" ); document.write( "35 mi/hr
\n" ); document.write( "---------------
\n" ); document.write( "check:
\n" ); document.write( "\"+11+=+%28+s+%2B+s+%2B+15+%29%2A%28+1%2F5+%29+\"
\n" ); document.write( "\"+11+=+55%2A%28+1%2F5+%29+\"
\n" ); document.write( "\"+55+=+55+\"
\n" ); document.write( "OK
\n" ); document.write( "
\n" );