document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=11429>Question 11429</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A passenger train and a freight train start at the same point at the same time  and travel in opposite directions. The passenger train travels twice as fast as the freight train. In 4 hours they are 396 miles apart. What is the rate of each train  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #5929 by </B><A HREF=/tutors/aboutme.mpl?userid=askmemath><B>askmemath(368)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=askmemath><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=5929\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the speed of the 1st train = X<BR>\n" );
document.write( "Then speed of second = 2X<BR>\n" );
document.write( "Each travels for 4 hours<BR>\n" );
document.write( "So distance covered by each = 4X+8X = 12X<BR>\n" );
document.write( "But this is given as 396<BR>\n" );
document.write( "So 12X = 396<BR>\n" );
document.write( "X = 396/12 = 35.5mph<BR>\n" );
document.write( "Speed of the second train = 2 x 35.5 = 71mph </SPAN>\n" );
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