document.write( "Question 970238: i have a math problem that says to build (draw)a rectangular platform with a perimeter of 74 feet and an area of 340 square feet. how would I make this on paper
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Algebra.Com's Answer #592886 by macston(5194)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "L=length; W=width; P=perimeter; A=area
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\n" ); document.write( "P=2(L+W)
\n" ); document.write( "74ft=2(L+W)
\n" ); document.write( "37ft=L+W
\n" ); document.write( "37ft-W=L Use this to substitute for L.
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\n" ); document.write( "\"A=LW\" Substitute for L from above.
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\n" ); document.write( "\"340ft%5E2=%2837ft-W%29W\"
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\n" ); document.write( "\"340ft%5E2=37Wft-W%5E2\" Add \"W%5E2-37Wft\" to each side
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\n" ); document.write( "\"W%5E2-37Wft%2B340ft%5E2=0\"
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\n" ); document.write( "\"%28W-20ft%29%28W-17ft%29=0\"
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\n" ); document.write( "\"W-20ft=0\" \"or\" \"W-17ft=0\"
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\n" ); document.write( "\"W=20ft\" \"or\" \"W=17ft\"
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\n" ); document.write( "The width will be either 17 feet or 20 feet and the length will be the other.
\n" ); document.write( "For instance, with a width of 17 feet, the length would be 20 feet.
\n" ); document.write( "With a scale of 48:1 (4 feet=1 inch), you would draw a rectangle 5 inches long by 4 1/4 inches wide.\r
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