document.write( "Question 970231: A jar contains 50 nickels and dimes worth $4.30. How many of each kind of coin are in the jar?
\n" );
document.write( " \n" );
document.write( "
Algebra.Com's Answer #592873 by macston(5194)![]() ![]() You can put this solution on YOUR website! . \n" ); document.write( "N=Number of nickels; D=number of dimes \n" ); document.write( "N+D=50 \n" ); document.write( "D=50-N Use this to substitute for D below. \n" ); document.write( ". \n" ); document.write( "$0.05N+$0.10D=$4.30 (This converts number of coins to value) Substitute for D. \n" ); document.write( "$0.05N+$0.10(50-N)=$4.30 \n" ); document.write( "$0.05N+$5.00-$0.10N=$4.30 Subtract $5.00 from each side. \n" ); document.write( "-$0.05N=-$0.70 Divide each side by -$0.05. \n" ); document.write( "N=14 ANSWER 1: There are 14 nickels in the jar. \n" ); document.write( ". \n" ); document.write( "D=50-N=50-14=36 ANSWER 2: There are 36 dimes in the jar. \n" ); document.write( ". \n" ); document.write( "CHECK: \n" ); document.write( "$0.05N+$0.10D=$4.30 \n" ); document.write( "$0.05(14)+$0.10(36)=$4.30 \n" ); document.write( "$0.70+$3.60=$4.30 \n" ); document.write( "$4.30=$4.30 \n" ); document.write( " |