document.write( "Question 970231: A jar contains 50 nickels and dimes worth $4.30. How many of each kind of coin are in the jar?
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Algebra.Com's Answer #592873 by macston(5194)\"\" \"About 
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\n" ); document.write( "N=Number of nickels; D=number of dimes
\n" ); document.write( "N+D=50
\n" ); document.write( "D=50-N Use this to substitute for D below.
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\n" ); document.write( "$0.05N+$0.10D=$4.30 (This converts number of coins to value) Substitute for D.
\n" ); document.write( "$0.05N+$0.10(50-N)=$4.30
\n" ); document.write( "$0.05N+$5.00-$0.10N=$4.30 Subtract $5.00 from each side.
\n" ); document.write( "-$0.05N=-$0.70 Divide each side by -$0.05.
\n" ); document.write( "N=14 ANSWER 1: There are 14 nickels in the jar.
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\n" ); document.write( "D=50-N=50-14=36 ANSWER 2: There are 36 dimes in the jar.
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\n" ); document.write( "CHECK:
\n" ); document.write( "$0.05N+$0.10D=$4.30
\n" ); document.write( "$0.05(14)+$0.10(36)=$4.30
\n" ); document.write( "$0.70+$3.60=$4.30
\n" ); document.write( "$4.30=$4.30
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