document.write( "Question 970231: A jar contains 50 nickels and dimes worth $4.30. How many of each kind of coin are in the jar?
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Algebra.Com's Answer #592871 by AnlytcPhil(1807)\"\" \"About 
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document.write( "Let the number of nickels be x\r\n" );
document.write( "Then the number of dimes, using\r\n" );
document.write( "ONE PART = TOTAL MINUS OTHER PART,\r\n" );
document.write( "is 50-x.\r\n" );
document.write( "                      Value      Value\r\n" );
document.write( "Type       Number       of         of\r\n" );
document.write( " of          of        EACH       ALL\r\n" );
document.write( "coin        coins      coin      coins\r\n" );
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document.write( "nickels      x       $0.05    $0.05x\r\n" );
document.write( "dimes      50-x      $0.10    $0.10(50-x)\r\n" );
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document.write( "TOTALS      50        -----   $4.30\r\n" );
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document.write( " The equation comes from the column on the right\r\n" );
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document.write( "  \"%28matrix%284%2C1%2CValue%2Cof%2CALL%2Cnickels%29%29\"\"%22%22%2B%22%22\"\"%28matrix%284%2C1%2CValue%2Cof%2CALL%2Cdimes%29%29\"\"%22%22=%22%22\"\"%28matrix%285%2C1%2CTotal%2Cvalue%2Cof%2CALL%2Ccoins%29%29\"\r\n" );
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document.write( "   0.05x + 0.10(50-x) = 4.30\r\n" );
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document.write( "Get rid of decimals by multiplying every term by 100:\r\n" );
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document.write( "        5x + 10(50-x) = 430\r\n" );
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document.write( "       5x + 500 - 10x = 430\r\n" );
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document.write( "            -5x + 500 = 430\r\n" );
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document.write( "                  -5x = -70\r\n" );
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document.write( "                    x = 14 = the number of nickels.\r\n" );
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document.write( "The number of dimes is 50-x or 50-14 or 36 dimes.\r\n" );
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document.write( "Checking:  14 nickels is $0.70 and 36 dimes is $3.60\r\n" );
document.write( "            That's 50 coins.\r\n" );
document.write( "            And indeed $0.70 + $3.60 = $4.30\r\n" );
document.write( "Edwin

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