document.write( "Question 970218: Find the values for x and y using the given slope.
\n" ); document.write( "m= 5/3 and (3,7), (x,2), (-3,y)
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Algebra.Com's Answer #592859 by Boreal(15235)\"\" \"About 
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slope using first two points, (3,7) and (x,2) is (-5)/x-3 ; we subtract the 7 from the 2 (difference in y) and 3 from x (difference in x). Notice we have an x generic for slope and an algebraic x. \r
\n" ); document.write( "\n" ); document.write( "slope using the first and third points will be equal to the first if we have a line. That slope is (y-7)/(-3-3) or (y-7)/-6\r
\n" ); document.write( "\n" ); document.write( "Set them equal to 5/3 since that is the numerical value of the slope given.\r
\n" ); document.write( "\n" ); document.write( "[-5/(x-3)]=5/3
\n" ); document.write( "Cross multiply. -15=5(x-3)
\n" ); document.write( "-15=5x-15 by distributing.
\n" ); document.write( "add 15 to both sides.
\n" ); document.write( "0=5x; x=0\r
\n" ); document.write( "\n" ); document.write( "[(y-7)/-6]=5/3
\n" ); document.write( "Cross multiply
\n" ); document.write( "3(y-7)=(-6)*5)
\n" ); document.write( "3y-21=-30
\n" ); document.write( "3y=-9, adding 21 to both sides
\n" ); document.write( "y=-3, dividing both sides by 3\r
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\n" ); document.write( "\n" ); document.write( "(3,7)
\n" ); document.write( "(0,2)
\n" ); document.write( "(-3, -3) are the points.\r
\n" ); document.write( "\n" ); document.write( "Check slope between the points
\n" ); document.write( "(3,7) and (0,2); (2-7))/(0-3) ; -5/-3 or 5/3
\n" ); document.write( "(0,2) and (-3,-3); (-3-2)/-3 ; -5/-5 or 5/3\r
\n" ); document.write( "\n" ); document.write( "x=0
\n" ); document.write( "y=-3\r
\n" ); document.write( "\n" ); document.write( "Notice that the points are on the line y=(5/3)x +2\r
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\n" ); document.write( "\n" ); document.write( "\"graph%28300%2C300%2C-5%2C5%2C-5%2C10%2C%285%2F3%29x%2B2%29\"
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