document.write( "Question 970181: Find all solutions if 0° ≤ θ < 360°. When necessary, round your answers to the nearest tenth of a degree. (Enter your answers as a comma-separated list.)\r
\n" ); document.write( "\n" ); document.write( "sin^2 2θ − 7 sin 2θ − 1 = 0
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Algebra.Com's Answer #592848 by lwsshak3(11628) $\"\"$ $\"About$

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Find all solutions if 0° ≤ θ < 360°. When necessary, round your answers to the nearest tenth of a degree. (Enter your answers as a comma-separated list.)
\n" ); document.write( "sin^2 2θ − 7 sin 2θ − 1 = 0
\n" ); document.write( "***
\n" ); document.write( "sin^2 2θ − 7 sin 2θ − 1 = 0
\n" ); document.write( "solve for sin 2θ by quadratic formula:
\n" ); document.write( " $\"sin+2%26%23952%3B+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"$
\n" ); document.write( "a=1, b=-7, c=-1
\n" ); document.write( "ans:
\n" ); document.write( "sin 2θ=7.14 (reject, (-1 < sin 2θ < 1))
\n" ); document.write( "or
\n" ); document.write( "sin 2θ=-0.14
\n" ); document.write( "2θ=188.1˚, 352.0˚ (in quadrants III and IV where sin<0)
\n" ); document.write( "θ=94.0˚, 176.0˚ \n" ); document.write( "

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