document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=970183>Question 970183</A>: <I><SPAN STYLE=\"word-break: break-all;\"> solve for x & y when x/3 + y/4= 19/12 AND x/2 - y/5= -63/80 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #592831 by </B><A HREF=/tutors/aboutme.mpl?userid=amarjeeth123><B>amarjeeth123(569)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=amarjeeth123><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=592831\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x/3 + y/4= 19/12<BR>\n" );
document.write( "Multiplying on both sides by 12 we get,<BR>\n" );
document.write( "4x+3y=19.........equation 1<BR>\n" );
document.write( "x/2 - y/5= -63/80<BR>\n" );
document.write( "Multiplying on both sides by 80 we get,<BR>\n" );
document.write( "40x-16y=-63......equation 2<BR>\n" );
document.write( "Multiplying equation 1 by 10 we get,<BR>\n" );
document.write( "40x+30y=190......equation 3<BR>\n" );
document.write( "Subtracting equation 2 from equation 3 we get,<BR>\n" );
document.write( "40x+30y-40x+16y=190+63<BR>\n" );
document.write( "46y=253<BR>\n" );
document.write( "y=253/46.<BR>\n" );
document.write( "x=(19-759/46)/4=115/184. </SPAN>\n" );
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