document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=970128>Question 970128</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Calculate the area of a sector of a circle with radius 4&#8201;km that subtends an angle (5pi/8) Enter your answer in square kilometers?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #592794 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=592794\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  Calculate the area of a sector of a circle with radius 4&#8201;km that subtends an angle (5pi/8) Enter your answer in square kilometers? <BR>\n" );
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document.write( "Area of the circle:: pi*4^2 = 16pi <BR>\n" );
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document.write( "Proportion::<BR>\n" );
document.write( "sector area/(5pi/8) = circle area/2pi<BR>\n" );
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document.write( "sector area [5pi/8][16pi/2pi]<BR>\n" );
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document.write( "Ans:: 5 km^2<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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