document.write( "Question 970109: You invested $10,000 in two accounts, one paying 8% and the other account paying 10% annual interest. At the end of the year, the total interest from these investments was $940. How much was invested at each rate? \n" ); document.write( "
Algebra.Com's Answer #592787 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! You invested $10,000 in two accounts, one paying 8% and the other account paying 10% annual interest. At the end of the year, the total interest from these investments was $940. How much was invested at each rate? \n" ); document.write( "------- \n" ); document.write( "Equation: \n" ); document.write( "interest + interest = interest \n" ); document.write( "0.08*x + 0.10(10000-x) = 940 \n" ); document.write( "----- \n" ); document.write( "8x + 10*10000 - 10x = 94000 \n" ); document.write( "-2x = -6000 \n" ); document.write( "------------------ \n" ); document.write( "x = $3000 (amt. invested at 8%) \n" ); document.write( "---- \n" ); document.write( "10,000-x = $7,000 (amt. invested at 10%)\r \n" ); document.write( "\n" ); document.write( "-------------------- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "-------------- \n" ); document.write( " |