document.write( "Question 970109: You invested $10,000 in two accounts, one paying 8% and the other account paying 10% annual interest. At the end of the year, the total interest from these investments was $940. How much was invested at each rate? \n" ); document.write( "
Algebra.Com's Answer #592787 by stanbon(75887)\"\" \"About 
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You invested $10,000 in two accounts, one paying 8% and the other account paying 10% annual interest. At the end of the year, the total interest from these investments was $940. How much was invested at each rate?
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\n" ); document.write( "Equation:
\n" ); document.write( "interest + interest = interest
\n" ); document.write( "0.08*x + 0.10(10000-x) = 940
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\n" ); document.write( "8x + 10*10000 - 10x = 94000
\n" ); document.write( "-2x = -6000
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\n" ); document.write( "x = $3000 (amt. invested at 8%)
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\n" ); document.write( "10,000-x = $7,000 (amt. invested at 10%)\r
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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