document.write( "Question 970109: You invested $10,000 in two accounts, one paying 8% and the other account paying 10% annual interest. At the end of the year, the total interest from these investments was $940. How much was invested at each rate? \n" ); document.write( "
Algebra.Com's Answer #592786 by Boreal(15235)\"\" \"About 
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Amount in Account 1 is x
\n" ); document.write( "Amount in Account 2 is $10,000-x; Their sum is $10,000\r
\n" ); document.write( "\n" ); document.write( "Account 1 pays .08x per year I=PRT\r
\n" ); document.write( "\n" ); document.write( "Account 2 pays (.1)(10.000-x) per year\r
\n" ); document.write( "\n" ); document.write( "Their sum is $940\r
\n" ); document.write( "\n" ); document.write( ".08x + 1000-.10x=940 We distribute the .1 over the (10,000-x)\r
\n" ); document.write( "\n" ); document.write( "Collect terms and subtract 1000 from both sides
\n" ); document.write( "-0.02x=-$60
\n" ); document.write( "Divide by (-1)
\n" ); document.write( "0.02 x=60
\n" ); document.write( "Multiply by 50 (or divide by 0.02)
\n" ); document.write( "x=3000 @ 8%, $240/year ACCOUNT 1
\n" ); document.write( "10,000-x =$7000 @ 10%, $740 year ACCOUNT 2\r
\n" ); document.write( "\n" ); document.write( "Their sum is $940.\r
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