document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=970075>Question 970075</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve for x. (1/3) lne^(3x)- 3e^(lnx)=12. There  is no solution but I don't know how to prove that.  Please help. Thank you. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #592749 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=592749\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> ln (e ^ something) = something.  ln and e are opposites, like dividing and multiplying.\r<BR>\n" );
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document.write( "(1/3) lne^(3x)- 3e^(lnx)=12; e^lnx =1\r<BR>\n" );
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document.write( "(1/3)* 3x -3 =12\r<BR>\n" );
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document.write( "x -3 =12<BR>\n" );
document.write( "x=15\r<BR>\n" );
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document.write( "Check this\r<BR>\n" );
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document.write( "(1/3) ln e^(45)- 3 e^(ln 15)=12\r<BR>\n" );
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document.write( "15-15 =0  \r<BR>\n" );
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document.write( "but 0 does not equal 12.  No solution\r<BR>\n" );
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document.write( "Try ln (1)=0; (1/3)* ln e^3-3e(0)=12; (1/3)*3 -0=12, which is not true.\r<BR>\n" );
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