document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=970072>Question 970072</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A plane flies 460 mph in calm air. Flying with the wind, the plane can travel 1560 miles in the same amount of time that it takes to travel 1200 miles flying against the wind. Find the rate of wind. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #592733 by </B><A HREF=/tutors/aboutme.mpl?userid=macston><B>macston(5194)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=macston><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=macston><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=592733\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> .<BR>\n" );
document.write( "w=rate of wind<BR>\n" );
document.write( "Time=distance/rate Since times are the same:<BR>\n" );
document.write( "1560mi/460mph+w=1200mi/460mph-w Cross multiply.<BR>\n" );
document.write( "1560mi(460mph-w)=1200mi(460mph+w)<BR>\n" );
document.write( "717600mi^2/h-(1560w)mi=552000mi^2/h+(1200w)mi Subtract 552000mi^2/h from each side.<BR>\n" );
document.write( "165600mi^2/h-(1560w)mi=(1200w)mi Add (1560w)mi to each side.<BR>\n" );
document.write( "165600mi^2/h=(2760w)mi Divide each side by 2760mi<BR>\n" );
document.write( "60 mi/h=w<BR>\n" );
document.write( "ANSWER: The rate of the wind was 60 miles per hour.<BR>\n" );
document.write( ".<BR>\n" );
document.write( "CHECK:<BR>\n" );
document.write( "1560mi/460mph+w=1200mi/460mph-w<BR>\n" );
document.write( "1560mi/460mph+60mph=1200mi/460mph-60mph<BR>\n" );
document.write( "1560mi/520mph=1200mi/400mph<BR>\n" );
document.write( "3hrs=3hrs </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );