document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=970075>Question 970075</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve for x. (1/3) lne^(3x)- 3e^(lnx)=12. There  is no solution but I don't know how to prove that.  Please help. Thank you. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #592728 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=592728\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Solve for x. (1/3) lne^(3x)- 3e^(lnx)=12<BR>\n" );
document.write( "(1/3)*(3x)- 3x = 12<BR>\n" );
document.write( "x - 3x = 12<BR>\n" );
document.write( "x = -6<BR>\n" );
document.write( "--------------<BR>\n" );
document.write( "--> ln of a negative number, not allowed --> no solution </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );