document.write( "Question 961845: Mike gave his friend 53 coins that total $3.65. He gave him nickels and dimes. How many nickels and dimes there Mike give his friend? \n" ); document.write( "

Algebra.Com's Answer #592724 by AnlytcPhil(1810) $\"\"$ $\"About$

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document.write( "Let the number of nickels be x\r\n" );
document.write( "Then the number of dimes, using\r\n" );
document.write( "ONE PART = TOTAL MINUS OTHER PART,\r\n" );
document.write( "is 53-x.\r\n" );
document.write( "                      Value      Value\r\n" );
document.write( "Type       Number       of         of\r\n" );
document.write( " of          of        EACH       ALL\r\n" );
document.write( "coin        coins      coin      coins\r\n" );
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document.write( "nickels      x         $0.05    $0.05x\r\n" );
document.write( "dimes      53-x        $0.10    $0.10(53-x)\r\n" );
document.write( "-------------------------------------------\r\n" );
document.write( "TOTALS      53        -----     $3.65\r\n" );
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document.write( " The equation comes from the column on the right\r\n" );
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document.write( "  \r\n" );
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document.write( " 0.05x + 0.10(53-x) = 3.65\r\n" );
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document.write( "Get rid of decimals by multiplying every term by 100:\r\n" );
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document.write( "     5x + 10(53-x) = 365\r\n" );
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document.write( "    5x + 530 - 10x = 365\r\n" );
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document.write( "         -5x + 530 = 365\r\n" );
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document.write( "               -5x = -165\r\n" );
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document.write( "                 x = 33 = the number of nickels.\r\n" );
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document.write( "The number of dimes is 53-x or 53-33 or 20 dimes.\r\n" );
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document.write( "Checking:  33 nickels is $1.65 and 20 dimes is $2.00\r\n" );
document.write( "            That's 53 coins.\r\n" );
document.write( "            And indeed $1.65 + $2.00 = $3.65\r\n" );
document.write( "Edwin

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