document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=969940>Question 969940</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the 43rd term of -124, -122, -120... </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #592642 by </B><A HREF=/tutors/aboutme.mpl?userid=amarjeeth123><B>amarjeeth123(569)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=amarjeeth123><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=592642\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The given series is in arithmetic progression.<BR>\n" );
document.write( "First term a=-124<BR>\n" );
document.write( "Common difference d=2<BR>\n" );
document.write( "Nth term an=a+(n-1)d<BR>\n" );
document.write( "a43=-124+(43-1)2=84-124=-40<BR>\n" );
document.write( "Answer=-40 </SPAN>\n" );
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