document.write( "Question 969860: Find the sum.
\n" ); document.write( "(3/8)+(3/4)+(3/2)+3+...+192 \n" ); document.write( "

Algebra.Com's Answer #592600 by rothauserc(4718) $\"\"$ $\"About$

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(3/8)+(3/4)+(3/2)+3+...+192
\n" ); document.write( "this is a geometric series, the formula for the nth term in a geometric series is
\n" ); document.write( "xn = ar^(n-1) where a is the first term and r is the common ratio
\n" ); document.write( "in this case a = (3/8) and r = 2, we want to find n for the term 192
\n" ); document.write( "192 = (3/8) * 2^(n-1)
\n" ); document.write( "2^(n-1) = 512
\n" ); document.write( "n = 10
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\n" ); document.write( "now we want to find the sum of the first 10 terms of our geometric series
\n" ); document.write( "sum = a * ((1-r^n) / (1-r)) = (3/8)*((1-(2^10)) / (1-2)) = 383.625
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