document.write( "Question 969854: A rowing team rowed
\n" ); document.write( "60 miles while going with the current in the same amount of time as it took to row 30 miles going against the current. The rate of the current was 3 miles per hour. Find the rate of the rowing team in still water. \n" ); document.write( "

Algebra.Com's Answer #592590 by lwsshak3(11628) $\"\"$ $\"About$

You can put this solution on YOUR website!
A rowing team rowed 60 miles while going with the current in the same amount of time as it took to row 30 miles going against the current. The rate of the current was 3 miles per hour. Find the rate of the rowing team in still water.
\n" ); document.write( "***
\n" ); document.write( "let x=rate of the rowing team in still water
\n" ); document.write( "x+3=rate of the rowing team going with the current
\n" ); document.write( "x-3=rate of the rowing team going against the currrent
\n" ); document.write( "travel time=distance/speed (equal for downstream and upstream)
\n" ); document.write( "..
\n" ); document.write( " $\"60%2F%28x%2B3%29=30%2F%28x-3%29\"$
\n" ); document.write( "30(x+3)=60(x-3)
\n" ); document.write( "30x+90=60x-180
\n" ); document.write( "30x=270
\n" ); document.write( "x=9
\n" ); document.write( "rate of the rowing team in still water= 9 mph \n" ); document.write( "

\n" );