document.write( "Question 969837: Referring to the figure, given
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Algebra.Com's Answer #592579 by Edwin McCravy(20056)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "It will help you if you will redraw the triangles so they\r\n" );
document.write( "are turned the same way, and so that their bottom sides are\r\n" );
document.write( "at the same level.  They give them to you turned in different \r\n" );
document.write( "ways just to confuse you as to which sides correspond.\r\n" );
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document.write( "Redraw them like this so you can compare corresponding sides:\r\n" );
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document.write( "The vertical side KL of the first triangle corresponds to the vertical\r\n" );
document.write( "side ST of the second triangle \r\n" );
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document.write( "in the same way that\r\n" );
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document.write( "The horizontal side JL on the first triangle corresponds to the horizontal\r\n" );
document.write( "side RT of the second triangle.\r\n" );
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document.write( "x compares to 10 just as 15 compares to 25.\r\n" );
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document.write( "      x is to 10 as 15 is to 25\r\n" );
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document.write( "\"is to\" is \"over\" and \"as\" is \"equals\".\r\n" );
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document.write( "   \"x%2F10\"\"%22%22=%22%22\"\"15%2F25\"\r\n" );
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document.write( "Solve that by cross-multiplying then dividing.\r\n" );
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document.write( "Edwin
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