document.write( "Question 969850: Solve by completing the square. x^2-6x-4=0 \n" ); document.write( "
Algebra.Com's Answer #592576 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
\"+x%5E2++-+6x+-+4+=+0+\"
\n" ); document.write( "Add \"+4+\" to both sides
\n" ); document.write( "\"+x%5E2++-+6x+=+4+\"
\n" ); document.write( "Take \"+1%2F2+\" of the coefficient of The
\n" ); document.write( "\"+x+\" term, square it, and add it to both sides
\n" ); document.write( "----------------------------
\n" ); document.write( "\"+x%5E2+-+6x+%2B+%28+-6%2F2+%29%5E2+=+4+%2B+%28+-6%2F2+%29%5E2+\"
\n" ); document.write( "\"+x%5E2+-+6x+%2B+9+=+4+%2B+9+\"
\n" ); document.write( "\"+x%5E2+-+6x+%2B+9+=+13+\"
\n" ); document.write( "\"+%28+x+-+3+%29%5E2+=+13+\"
\n" ); document.write( "Take the square root of both sides
\n" ); document.write( "\"+x+-+3+=+sqrt%2813%29+\"
\n" ); document.write( "\"+x+=+3+%2B+sqrt%2813%29+\"
\n" ); document.write( "And also, taking the negative square root,
\n" ); document.write( "\"+x+=+3+-+sqrt%2813%29+\"
\n" ); document.write( "---------------------
\n" ); document.write( "check answer:
\n" ); document.write( "\"+x%5E2++-+6x+-+4+=+0+\"
\n" ); document.write( "\"+%28+3+-+sqrt%2813%29+%29%5E2+-+6%2A%28+3+-+sqrt%2813%29+%29++-+4+=+0+\"
\n" ); document.write( "\"+9+-+6%2Asqrt%2813%29+%2B+13+-+18+%2B+6%2Asqrt%2813%29+-+4+=+0+\"
\n" ); document.write( "\"+9+%2B+13+-+18+-+4+=+0+\"
\n" ); document.write( "\"+22+-+22+=+0+\"
\n" ); document.write( "OK
\n" ); document.write( "You can check \"+x+=+3+%2B+sqrt%2813%29+\"\r
\n" ); document.write( "\n" ); document.write( "
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