document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=969823>Question 969823</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A ball is thrown upward from a height of 15 feet with an initial velocity of 5 ft/s. use the formula h(t) = -16t^2 + 5t + 15 what is the maximum height the maximum height of the ball? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #592575 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=592575\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A ball is thrown upward from a height of 15 feet with an initial velocity of 5 ft/s. use the formula h(t) = -16t^2 + 5t + 15 what is the maximum height the maximum height of the ball?<BR>\n" );
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document.write( " h(t) = -16t^2 + 5t + 15<BR>\n" );
document.write( "complete the square:<BR>\n" );
document.write( " h(t) = -16(t^2 - (5/16)t+(25/1024))+25/64 + 960/64<BR>\n" );
document.write( " h(t) = -16(t- (5/32))^2)+985/64<BR>\n" );
document.write( "This is an equation of a parabola that opens downward with vertex at (5/32,985/64)<BR>\n" );
document.write( "maximum height of the ball=985/64&#8776;15.39 ft </SPAN>\n" );
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