document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=969776>Question 969776</A>: <I><SPAN STYLE=\"word-break: break-all;\"> cos x = -&#8730;2/2 over (0, 2pi) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #592528 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=592528\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Cos (sqrt (2)/2) is at 45 degrees, or pi/4 radians.  That, however is positive.  It becomes negative in the second and third quadrants.  Each of those is pi/2  more.\r<BR>\n" );
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document.write( "pi/4+ pi/2= 3 pi/4   That is one solution.<BR>\n" );
document.write( "3pi/4+pi/2=5 pi/4  That is the other solution.\r<BR>\n" );
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document.write( "In degrees, it is 135 and 225.\r<BR>\n" );
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