document.write( "Question 969740: Jack would like to erect a fence on all four sides of his new garden with an area of 225m^2. The fencing will cost him $35 per metre. In order to use the least fencing he would like the garden to be a minimum. The fence will be supported by wooden fence poles, approximately 1.5 m apart and a gate 1.5 m long, made of the same fence can be placed between any two poles. Each wooden fence pole would cost $9.50\r
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\n" ); document.write( "\n" ); document.write( "1. Calculate the lenght of each side of the garden\r
\n" ); document.write( "\n" ); document.write( "2.How many metres of fencing will he need?\r
\n" ); document.write( "\n" ); document.write( "3. How many fence poles will he need?\r
\n" ); document.write( "\n" ); document.write( "4. How much will the fencing and the fence poles, excluding the gate, cost him?\r
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\n" ); document.write( "\n" ); document.write( "(Please I really need help)
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Algebra.Com's Answer #592519 by Boreal(15235)\"\" \"About 
You can put this solution on YOUR website!
A square is the rectangle that minimizes the perimeter for a given area. Here is why without proving (first). If a rectangle has area 225 m^2, 15^2 (perimeter 4*15m=60m) is the best. For 25*9=225 , the perimeter is 68. For 45 *5=225, The perimeter is 100. The proof is much easier with calculus, but here is how I would go about it.\r
\n" ); document.write( "\n" ); document.write( "Let x and y be the length and the width, respectively.
\n" ); document.write( "Then 2x + 2y =perimeter; the area is xy\r
\n" ); document.write( "\n" ); document.write( "2x= perimeter-2y
\n" ); document.write( "xy, or the area, now become (perimeter-2y) y =perimeter*y-2y^2
\n" ); document.write( "This is a parabola, with the vertex at -b/2a or -(perimeter)/-2 or half of the perimeter.
\n" ); document.write( "So y in the area formula is half the perimeter. That means x has to be half the perimeter as well.
\n" ); document.write( "I don't see the gate as adding or subtracting from the 60 m perimeter.\r
\n" ); document.write( "\n" ); document.write( "There are 4 corner poles. There are 9 poles between each corner, which would be 36 poles in between..\r
\n" ); document.write( "\n" ); document.write( "x=y and x^2=225 m^2, so x and y are both 15 m. \r
\n" ); document.write( "\n" ); document.write( "The length of each side is 15 m\r
\n" ); document.write( "\n" ); document.write( "Fencing needed = 60 m. (including 1.5 m for the gate. I think that needs to be mentioned)\r
\n" ); document.write( "\n" ); document.write( "Fencing poles needed=40\r
\n" ); document.write( "\n" ); document.write( "Cost is 60*35 for fencing=$2100. 60 meters *$35/meter.
\n" ); document.write( "Cost of poles is 40*$9.50=$380
\n" ); document.write( "I get $2480 MINUS the cost of the fence, which is $35*1.5 meters or $52.50
\n" ); document.write( "Cost now is $2422.50.\r
\n" ); document.write( "\n" ); document.write( "I am hoping there are no tricks with the poles and the gate. \r
\n" ); document.write( "\n" ); document.write( "By the way, the maximum product for a given pair of numbers with a constant sum is when the numbers are the same. It is sort of the same idea. For a given amount of fence, you maximize the area it encloses when you make it a square. Here, you have a given area, so you are looking at minimizing the amount of fence. \r
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