document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=969743>Question 969743</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A garden has the shape of a right triangle with one leg 4 meters longer than the other. The hypotenuse is 4 meters less than twice the length of the shorter leg. What is the length of the shorter leg? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #592512 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=592512\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Leg 1 is X meters (all units are meters)<BR>\n" );
document.write( "Leg 2 is X+4<BR>\n" );
document.write( "Hypotenuse is (2X-4)  Twice the length of shorter leg minus 4\r<BR>\n" );
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document.write( "Pythagorean Theorem<BR>\n" );
document.write( "X^2  + (X+4)^2= (2X-4)^2\r<BR>\n" );
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document.write( "X^2 +(X+4)(X+4)=(2X-4)(2X-4)\r<BR>\n" );
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document.write( "X^2 + X^2 + 8X +16= 4X^2-16X+16\r<BR>\n" );
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document.write( "Move terms to right by subtracting 2 X^2 + 8X +16 from both sides.\r<BR>\n" );
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document.write( "0= 2X^2 -24 X    The 16s cancel each other.\r<BR>\n" );
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document.write( "2X(X-12)=0  Factoring.\r<BR>\n" );
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document.write( "X=0 (no sense)\r<BR>\n" );
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document.write( "X-12=0 ;  X=12\r<BR>\n" );
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document.write( "Leg 1 is 12<BR>\n" );
document.write( "Leg 2 is 16\r<BR>\n" );
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document.write( "Leg 3 is twice Leg 1 (24) - 4=20\r<BR>\n" );
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document.write( "This is a 12:16:20 right triangle,  4 times each side of a 3:4:5.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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