document.write( "Question 82403: The length of a rectangle is 4 in. more than twice its width. If the perimeter of the rectangle is 56 in., find the width of the rectangle.\r
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document.write( "Answer: The width is ______
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Algebra.Com's Answer #59251 by checkley75(3666)![]() ![]() ![]() You can put this solution on YOUR website! L=2W+4 \n" ); document.write( "P=2L+2W THUS \n" ); document.write( "56=2(2W+4)+2W \n" ); document.write( "56=4W+8+2W \n" ); document.write( "56=6W+8 \n" ); document.write( "6W=56-8 \n" ); document.write( "6W=48 \n" ); document.write( "W=48/6 \n" ); document.write( "W=8 IS THE WIDTH \n" ); document.write( "PROOF \n" ); document.write( "56=2(2*8+4)+2*8 \n" ); document.write( "56=2(16+4)+16 \n" ); document.write( "56=2*20=16 \n" ); document.write( "56=40+16 \n" ); document.write( "56=56 \n" ); document.write( " |