document.write( "Question 82403: The length of a rectangle is 4 in. more than twice its width. If the perimeter of the rectangle is 56 in., find the width of the rectangle.\r
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Algebra.Com's Answer #59251 by checkley75(3666)\"\" \"About 
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L=2W+4
\n" ); document.write( "P=2L+2W THUS
\n" ); document.write( "56=2(2W+4)+2W
\n" ); document.write( "56=4W+8+2W
\n" ); document.write( "56=6W+8
\n" ); document.write( "6W=56-8
\n" ); document.write( "6W=48
\n" ); document.write( "W=48/6
\n" ); document.write( "W=8 IS THE WIDTH
\n" ); document.write( "PROOF
\n" ); document.write( "56=2(2*8+4)+2*8
\n" ); document.write( "56=2(16+4)+16
\n" ); document.write( "56=2*20=16
\n" ); document.write( "56=40+16
\n" ); document.write( "56=56
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