document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=969739>Question 969739</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Three numbers are such that the second number is 5 more than the first and the thrid number is four more than three times the second. The sum of the three numbers is 134. Find the numbers. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #592501 by </B><A HREF=/tutors/aboutme.mpl?userid=satyareddy22><B>satyareddy22(84)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=satyareddy22><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=592501\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x,y,z be three numbers.<BR>\n" );
document.write( "x+y+z=134 (given)-------(1)<BR>\n" );
document.write( "y-x=5=>x=y-5--------(2)(given)<BR>\n" );
document.write( "z-3y=4=>z=4+3y------(3)(given)<BR>\n" );
document.write( "now,substituting(2)& (3) in (1)<BR>\n" );
document.write( "y-5+y+4+3y=134<BR>\n" );
document.write( "5y-1=134=>5y=134+1=135<BR>\n" );
document.write( "5y=135=>y=135/5=27<BR>\n" );
document.write( "y=27<BR>\n" );
document.write( "substituting y=27 in (2) &(3)<BR>\n" );
document.write( "x=y-5=27-5=22 =>x=22<BR>\n" );
document.write( "z=4+3(27)=85=>z=85<BR>\n" );
document.write( "Therefore three numbers are x=22,y=27,z=85<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );