document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=82404>Question 82404</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve the system by substitution.<BR>\n" );
document.write( "	2x + 2y = 14<BR>\n" );
document.write( "	          y = –3x + 9\r<BR>\n" );
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document.write( "Hint:  You must find both the x and the y values for full credit.\r<BR>\n" );
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document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #59250 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley75><B>checkley75(3666)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley75><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=59250\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> y=-3x+9 now substitute (-3x+9) for y in the other equation & solve for x.<BR>\n" );
document.write( "2x+2(-3x+9)=14<BR>\n" );
document.write( "2x-6x+18=14<BR>\n" );
document.write( "-4x=14-18<BR>\n" );
document.write( "-4x=-4<BR>\n" );
document.write( "x=-4/-4<BR>\n" );
document.write( "x=1 answer.<BR>\n" );
document.write( "y=-3*1+9<BR>\n" );
document.write( "y=-3+9<BR>\n" );
document.write( "y=6 answer.<BR>\n" );
document.write( "proof<BR>\n" );
document.write( "6=-3*1+9<BR>\n" );
document.write( "6=-3+9<BR>\n" );
document.write( "6=6 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );