document.write( "Question 969685: How do i solve: \r
\n" ); document.write( "\n" ); document.write( "\"+sin%28x%2F2%29+%2B+cos%28x%2F2%29+=+sqrt%28+2+%29+\"\r
\n" ); document.write( "\n" ); document.write( "Thanks!
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Algebra.Com's Answer #592495 by lwsshak3(11628)\"\" \"About 
You can put this solution on YOUR website!
\"+sin%28x%2F2%29+%2B+cos%28x%2F2%29+=+sqrt%28+2+%29+\"
\n" ); document.write( "\"sqrt%28%281-cosx%29%2F2%29+%2Bsqrt%28%281%2Bcosx%29%2F2%29++=+sqrt%28+2+%29+\"
\n" ); document.write( "square both sides:
\n" ); document.write( "\"%281-cosx%29%2F2+%2B2%2Asqrt%28%281-cosx%29%281%2Bcosx%29%2F4%29%2B%281%2Bcosx%29%2F2++=+2+\"
\n" ); document.write( "\"%281-cosx%29%2F2+%2B2%2Asqrt%28%281-cos%5E2%28x%29%29%2F4%29%2B%281%2Bcosx%29%2F2++=+2+\"
\n" ); document.write( "\"%281-cosx%29%2F2+%2B2%2Asqrt%28%28sin%5E2%28x%29%29%2F4%29%2B%281%2Bcosx%29%2F2++=+2+\"
\n" ); document.write( "\"%281-cosx%29%2F2+%2Bsinx%2B%281%2Bcosx%29%2F2++=+2+\"
\n" ); document.write( "sinx+1=2
\n" ); document.write( "sinx=1
\n" ); document.write( "x=π/2
\n" ); document.write( "check:
\n" ); document.write( "sin(x/2)+cos)x/2)=√2/2+√2/2=√2
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