document.write( "Question 969646: On a certain day, the temperature was 37 Fahrenheit at 10am and 49 fahrenheit at 1pm. if the temperature rose at a constant rate from 10am to 1pm on that day, what was the temperature at 11am? \n" ); document.write( "
Algebra.Com's Answer #592468 by MathTherapy(10553)\"\" \"About 
You can put this solution on YOUR website!
On a certain day, the temperature was 37 Fahrenheit at 10am and 49 fahrenheit at 1pm. if the temperature rose at a constant rate from 10am to 1pm on that day, what was the temperature at 11am?
\n" ); document.write( "
Let x be time, with starting time being x = 0. Then y is the temperature at a particular time of the day
\n" ); document.write( "We then get: \"f%28x%29+=+mx+%2B+b\"
\n" ); document.write( "Points: (0, 37) and (3, 49)
\n" ); document.write( "Slope or m = \"%2837+-+49%29%2F%280+-+3%29\", or m = 4
\n" ); document.write( "\"y+-+y%5B1%5D+=+m%28x+-+x%5B1%5D%29\"
\n" ); document.write( "\"y+-+37+=+4%28x+-+0%29\"
\n" ); document.write( "\"y+-+37+=+4x\"
\n" ); document.write( "
\n" ); document.write( "\"y+=+4x+%2B+37\", or \"f%28x%29+=+4x+%2B+37\" -------- Equation representing temperature at a certain time of the day
\n" ); document.write( "Since 11am is the 1st hour, or hour 1 after 10am, then \"f%28x%29+=+4x+%2B+37\" becomes: \"f%281%29+=+4%281%29+%2B+37\", or \"f%281%29+=+4+%2B+37\".
\n" ); document.write( "Therefore, temperature, 1 hour after 10am, or at 11am = \"highlight_green%2841%5Eo%29\" \n" ); document.write( "
\n" );